Algebra Questions

Multiple choice
  1. b2 = a(c + 1)2

  2. b2 = (c + a)2

  3. b = a2(c + 1)

  4. b = a(c + 1)2

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the roots of the quadratic equation be k*c and k*a. The sum of the roots is k(c + a) = -b/a, and the product of the roots is k^2 * a * c = c/a, which simplifies to k^2 = 1/a^2. Squaring the sum equation gives k^2 * (c + a)^2 = b^2 / a^2, and substituting k^2 = 1/a^2 yields b^2 = (c + a)^2.

Multiple choice
  1. S11 = S10 + S12

  2. 2S11 = S12 + S10

  3. 2S12 = S11 + S10

  4. S12 = S11 + S10

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Since alpha and beta are roots of x^2 - x - 1 = 0, they satisfy x^2 = x + 1. Multiplying by x^(n-2) gives x^n = x^(n-1) + x^(n-2). This linear recurrence holds for both alpha and beta, so S_n = 2023*alpha^n + 2024*beta^n also satisfies S_n = S_(n-1) + S_(n-2).

Multiple choice
  1. p > q

  2. p ≥ q

  3. p < q

  4. p ≤ q

  5. p = q or no relation can be established

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Eq I: 2p^2 - 7p + 6 = 0. (2p-3)(p-2)=0, p=1.5 or 2. Eq II: 4q^2 = 9, q^2 = 2.25, q = 1.5 or -1.5. Comparing: p=1.5, q=1.5 (p=q); p=2, q=1.5 (p>q); p=1.5, q=-1.5 (p>q); p=2, q=-1.5 (p>q). Thus p >= q.

Multiple choice
  1. 1 only

  2. 2 only

  3. Both 1 and 2

  4. Neither 1 nor 2

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The equation is (a+b+c)x^2 - 2(a+b)x + (a+b-c) = 0. Using the quadratic formula or testing values, if a,b,c > 0, the product of roots is (a+b-c)/(a+b+c). Statement 1 holds true under specific conditions, but statement 2 is not universally true for all negative a,b,c.

Multiple choice
  1. Only statement I alone is sufficient to answer the question.

  2. Only statement II alone is sufficient to answer the question.

  3. Both the statements together are sufficient to answer the question.

  4. Both the statements together are insufficient to answer the question.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Sum of roots = -(a+b) / (5c). We have two equations with three variables (a, b, c). Statement I: a = -c. Statement II: 3a + 2b + c = 5. Even with both, we cannot determine the ratio (a+b)/c uniquely.

Multiple choice
  1. pqr > 0

  2. p + q + r < 0

  3. p + q - r < 0

  4. p + q + r > 0

  5. a

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For py^2 + qy + r = 0 to have equal roots, the discriminant D = q^2 - 4pr = 0, so q^2 = 4pr. Since p and q are negative integers, q^2 is positive, so 4pr must be positive. Since p is negative, r must also be negative. If p, q, r are all negative, then p+q+r must be less than 0.

Multiple choice
  1. x = -2, 1/3

  2. x = -5/6, 2/3

  3. x = -5/3, 2/3

  4. x = -5/3, -2/3

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

3x^2 + 5x - 2 = 0. Factoring: 3x^2 + 6x - x - 2 = 0 => 3x(x+2) - 1(x+2) = 0 => (3x-1)(x+2) = 0. Roots are x = 1/3 and x = -2.