Consider the equation (1 - x)4 + (5 - x)4 = 82. What is the number of real roots of the equation?
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Consider the equation (1 - x)4 + (5 - x)4 = 82. What is the number of real roots of the equation?
0
2
4
8
Let f(x) = (1-x)^4 + (5-x)^4. This is a convex function. The minimum occurs at the midpoint of 1 and 5, which is x = 3. f(3) = (-2)^4 + (2)^4 = 16 + 16 = 32. Since 32 < 82, the function crosses 82 at two points (one less than 3, one greater than 3).
Use the symmetry method by letting the average of the bases be y, so 1 - x = 3 - y and 5 - x = 3 + y. Substituting these into the equation yields (3 - y)^4 + (3 + y)^4 = 82, which expands to 2(y^4 + 24y^2 + 81) = 82. Simplifying gives y^4 + 24y^2 + 40 = 0, and treating this as a quadratic in y^2 yields two positive solutions for y^2. Each positive solution produces two real values for y, resulting in 2 real roots for x.