Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Ten years ago, Rashmi was half of Garima in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

  1. 35 years

  2. 38 years

  3. 44 years

  4. 49 years

  5. 52 years
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let present ages be 3x and 4x (ratio 3:4). Ten years ago: (3x-10) = 1/2(4x-10). Solving: 3x-10 = 2x-5, so x=5. Present ages: 3×5=15 and 4×5=20. Total = 35 years, which is option A. Option B (38 years) would result from arithmetic error in solving the equation.

Multiple choice

A man is 5 years older than his sister and four times as old as his daughter. If the daughter becomes 20 years old after 4 years. Then what is the present age of his sister?

  1. 71 years

  2. 59 years

  3. 64 years

  4. 56 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the daughter's present age be x. After 4 years she becomes 20, so x = 16. The man is four times as old as his daughter, so man = 4 × 16 = 64 years. The man is 5 years older than his sister, so sister = 64 - 5 = 59 years.

Multiple choice

If three times of the son‘s age in years is included to the mother‘s age, the total is 75 and if two times of the mother‘s age is included to the son‘s age, the total is 80. So the son‘s age is? यदि वर्ष में बेटे की आयु के तीन गुना को मां की उम्र में शामिल किया गया है, तो कुल 75 है और यदि माता की आयु के दो गुना को बेटे की उम्र में शामिल किया गया है, तो कुल 80 है। बेटे की उम्र है?

  1. 15

  2. 18

  3. 14

  4. 22

  5. None of these इनमे से कोई नहीं
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let son's age = s, mother's age = m. First statement: 3s + m = 75. Second statement: s + 2m = 80. From first equation: m = 75 - 3s. Substitute into second: s + 2(75 - 3s) = 80, s + 150 - 6s = 80, 150 - 5s = 80, 5s = 70, s = 14. Son is 14 years old. Checking: m = 75 - 3(14) = 75 - 42 = 33. Verify second equation: 14 + 2(33) = 14 + 66 = 80. Correct.

Multiple choice

The ratio of present ages of Sri and Gowtham is 3: 4. Mahesh is 6 years older than Sri and two years younger than Gowtham. Find the sum of the present ages of Sri and Mahesh?

  1. 44 years

  2. 50 years

  3. 48 years

  4. 52 years

  5. None of these
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Let Sri's age = 3x and Gowtham's age = 4x. Mahesh is 6 years older than Sri: M = S + 6 = 3x + 6. Mahesh is 2 years younger than Gowtham: M = G - 2 = 4x - 2. Equating both expressions for M: 3x + 6 = 4x - 2, giving x = 8. Therefore: Sri = 3 × 8 = 24 years, Gowtham = 4 × 8 = 32 years, Mahesh = 24 + 6 = 30 years. Sum of Sri and Mahesh = 24 + 30 = 54 years. This doesn't match options A-D (44, 50, 48, 52 years), so 'None of these' is correct.

Multiple choice

$Let the present ages of the three persons be (4x), (7x), and (9x). Eight years ago, their ages were (4x - 8), (7x - 8), and (9x - 8). The sum of their ages eight years ago was 56. Therefore, we have the equation: ( (4x - 8) + (7x - 8) + (9x - 8) = 56 )$ $Simplifying the equation, we get: ( 20x - 24 = 56 )$ $Adding 24 to both sides, we have: ( 20x = 80 )$ $Dividing both sides by 20, we get: ( x = 4 )$ $Therefore, their present ages are: ( 4x = 4(4) = 16 ), ( 7x = 7(4) = 28 ), and ( 9x = 9(4) = 36 )$
  1. $20, 35, 45$
  2. $16, 28, 36$
  3. $8, 20, 28$
  4. $8, 14, 18$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The ages are in ratio 4:7:9, so let present ages be 4x, 7x, 9x. Eight years ago, their ages were 4x-8, 7x-8, 9x-8 with sum 56. Solving 20x-24=56 gives x=4. Present ages are 16, 28, 36. Option A (20,35,45) is 4x,7x,9x with x=5 but doesn't satisfy the 8-years-ago condition. Options C and D are incorrect calculations.

Multiple choice

3 years ago, ratio of age of A and B is 3:1. If the present age of B is 3/8 of the present age of A then what is the difference between their present ages (in years)?

  1. 25

  2. 30

  3. 35

  4. 40

  5. 45
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let present ages be A and B. Three years ago: (A-3)/(B-3) = 3/1, so A-3 = 3(B-3), giving A = 3B-6. Given B = (3/8)A. Substituting: A = 3(3/8)A - 6, so A = (9/8)A - 6, then A - (9/8)A = -6, giving (-1/8)A = -6, so A = 48. Then B = (3/8) × 48 = 18. Difference = 48 - 18 = 30 years. Option B is correct.

Multiple choice

Five years ago the sum of the ages of the father and his son was 40 years. Five years hence the age of the father will be three times his son’s age. The present age of the father is

  1. 40 years

  2. 35 years

  3. 45 years

  4. 30 years
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let son's present age = x, father's present age = y. Five years ago: (x-5)+(y-5)=40, so x+y=50. Five years hence: y+5=3(x+5), so y=3x+10. Substituting: x+(3x+10)=50, giving 4x=40, x=10. Therefore y=40. The father is currently 40 years old. Option A is correct.

Multiple choice

The mother is five times older than her son. After 4 years the sum of their ages will be 44 years. Then the son's age at present is

  1. 7 years

  2. 6 years

  3. 5 years

  4. 8 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the son's present age be x years. Then mother's age is 5x years. After 4 years: (x + 4) + (5x + 4) = 44. Solving: 6x + 8 = 44, so 6x = 36, giving x = 6. The son is currently 6 years old and the mother is 30 years old. After 4 years, they will be 10 and 34, summing to 44.