Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Five year ago, the age of a man was seven times the age of his son. The age of the man will be three times the age of his son in five year from now. The present age of the man and his son respectively are

  1. 68 year and 14 year

  2. 55 year and 15 year

  3. 54 year and 12 year

  4. 40 year and 10 year
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let present age of son = x Age of son before 5 years = x - 5 So, Present age of father = 7(x - 5) + 5 ……… (i) Age of son after 5 years = x + 5 Age of father after 5 years = 3(x + 5) So, present age of father = 3(x + 5) - 5 ……….(ii) Equating age of father, i.e. (i) and (ii):  7(x - 5) + 5 = 3(x + 5) - 5 7x – 35 + 5 = 3x + 15 - 5 7x - 3x = 15 - 5 + 35 - 5 4x = 40 x = 40/4. x (son) = 10, Father (3(10 + 5) - 5) =  40 years

Multiple choice

The ratio between the present ages of A and B is 4:5. If the ratio between their ages four years hence becomes 14:17, what is the B's age at present?

  1. 30

  2. 28

  3. 34

  4. Data inadequate
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let A's age be 4x and B's age be 5x. Four years hence, their ages will be (4x+4) and (5x+4). The ratio becomes (4x+4)/(5x+4) = 14/17. Cross-multiplying: 17(4x+4) = 14(5x+4), which gives 68x + 68 = 70x + 56. Solving: 2x = 12, so x = 6. B's present age is 5*6 = 30.

Multiple choice

A father is twice as old as his son. 20 years back, he was twelve times as old as the son. What are their present ages?

  1. 24,12

  2. 44,22

  3. 48,24

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the son's present age be x. The father's present age is 2x. Twenty years ago, their ages were (2x-20) and (x-20). At that time, the father was 12 times as old: (2x-20) = 12(x-20). Solving: 2x - 20 = 12x - 240, giving 10x = 220, so x = 22. Son is 22 years old, father is 44 years old.

Multiple choice

The present age of the father and the son are together 46 year. 5 year ago, the father was 11 times as old as his son. The age of the son after 5 year will be

  1. 13

  2. 14

  3. 12

  4. 11
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the son's present age be x. Father's age is 46-x. Five years ago: (46-x-5) = 11(x-5), meaning father was 11 times as old as the son. Solving: 41 - x = 11x - 55, giving 12x = 96, so x = 8. Son is 8 years old now. After 5 years, son will be 8 + 5 = 13 years old.

Multiple choice

The sum of the present age of the father and the son is 60 years. Six year ago, the father was 5 times as old as his son. The age of the son after 6 year will be

  1. 20

  2. 14

  3. 12

  4. 18
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the son's present age be x. Father's age is 60-x. Six years ago: (60-x-6) = 5(x-6), meaning father was 5 times as old as the son. Solving: 54 - x = 5x - 30, giving 6x = 84, so x = 14. Son is 14 years old now. After 6 years, son will be 14 + 6 = 20 years old.

Multiple choice

Sonu's father is 5 times as old as Sonu”. After 8 years his age will be thrice Sonu's age at that time. Find their present age?

  1. 30 year, 6 year

  2. 35 year, 7 year

  3. 40 year, 8 year

  4. 45 year, 9 year
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Sonu's present age be x. Father's age is 5x. After 8 years, Sonu will be (x+8) and father will be (5x+8). At that time, father will be thrice as old: (5x+8) = 3(x+8). Solving: 5x + 8 = 3x + 24, giving 2x = 16, so x = 8. Sonu is 8 years old and father is 40 years old.

Multiple choice

The sum of the ages of a father and son is 45 years. Five year ago the product to their ages was four times the father's age that time. The present age of the father and son respectively are?

  1. 39 year and 6 year

  2. 36 year and 9 year

  3. 25 year and 10 year

  4. None
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the father's age be F and the son's age be S. We know F + S = 45. Five years ago, their ages were (F-5) and (S-5). The product was four times the father's age: (F-5)(S-5) = 4(F-5). Assuming F ≠ 5, we can divide: S-5 = 4, so S = 9. Then F = 45 - 9 = 36. Checking: 5 years ago, ages were 31 and 4, product is 124, which is indeed 4*31 = 124. Present ages are 36 and 9.

Multiple choice

The ratio between the ages of A and Q four years ago was 5:6. If the total of their ages at present is 52 year, what is the ratio of their present ages?

  1. 4:5

  2. 8:9

  3. 7:8

  4. 6:7

  5. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the ages of A and Q be 5x and 6x, respectively. Now, (5x + 4) + (6x + 4) = 52 5x + 4 + 6x + 4 = 52 11x + 8 = 52 x = 4 Therefore, present age of A (5x) = 24 years and Q (6x) = 28 = Ratio of their present ages is 24 : 28 = 6 : 7

Multiple choice

A mother after 4 years will be twice the age of her daughter. The sum of their age is 46. What is the present age of the daughter?

  1. 14

  2. 15

  3. 16

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the daughter's present age be x. Mother's age is 46-x. After 4 years, daughter will be (x+4) and mother will be (46-x+4) = (50-x). At that time, mother will be twice as old: (50-x) = 2(x+4). Solving: 50 - x = 2x + 8, giving 3x = 42, so x = 14. Daughter is 14 years old.