Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

The ratio of ages of A and B is 2 : 3. After 10 years the ratio of their ages will be 4 : 5. So find the difference between their ages after 5 years.

  1. 10 years

  2. 5 years

  3. 15 years

  4. 20 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let current ages: A = 2x, B = 3x. After 10 years: (2x+10)/(3x+10) = 4/5. Cross-multiply: 5(2x+10) = 4(3x+10) → 10x+50 = 12x+40 → x = 5. After 5 years: A = 15, B = 20. Difference = 5 years. Option B is correct.

Multiple choice

Father's age is four times the daughter's age. After 8 years father's age will be thrice the daughter's age. What is daughter's age?

  1. 18 years

  2. 16 years

  3. 24 years

  4. 20 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let daughter's current age = x years. Father's current age = 4x years. After 8 years: daughter = x + 8, father = 4x + 8. Given: 4x + 8 = 3(x + 8). Solving: 4x + 8 = 3x + 24, so x = 16. Daughter is currently 16 years old. This can be verified: father is 64 now, after 8 years father will be 72 and daughter will be 24, and 72 = 3 × 24.

Multiple choice

2 years ago a mother was 4 times as old as her son, after 6 years from now, her age will become more than double her son's age by 10 years. What is the present ratio of their ages?

  1. 2 : 1

  2. 38 : 11

  3. 19 : 7

  4. 3 : 1
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let present ages be M (mother) and S (son). Two years ago: M-2 = 4(S-2) → M = 4S-6. After 6 years: M+6 = 2(S+6) + 10 → M = 2S + 22. Equating: 4S-6 = 2S+22 → 2S = 28 → S = 14, M = 50. Present ratio = 50:14 = 25:7. However 38:11 = 3.45:1 while 25:7 = 3.57:1. Let me verify: M-2 = 4(S-2) gives M = 4S-6. M+6 = 2(S+6)+10 = 2S+22 gives M = 2S+16. 4S-6 = 2S+16 → 2S = 22 → S = 11, M = 38. Ratio = 38:11.

Multiple choice

(\text{The ratio of the ages of mother and daughter is 3 : 1 and the sum of their ages is 64 years. So find the age of daughter after one year?})

  1. 17 years

  2. 16 years

  3. 26 years

  4. 27 years

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The ratio of mother's age to daughter's age is 3:1. Let the common ratio be x. Mother = 3x, Daughter = x. Their sum is 3x + x = 64, so 4x = 64 and x = 16. The daughter's current age is 16 years. After one year, the daughter will be 17 years old.

Multiple choice

5 years ago the average age of father and his son was 35 years and the ratio of their present ages is 4 : 1 so find the ratio of their ages after 10 years?
  1. $25 : 11$
  2. $42 : 11$
  3. $37 : 13$
  4. $13 : 37$

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let father's present age be 4x, son's be x. 5 years ago: (4x-5) + (x-5) = 70 (average 35, so sum 70). So 5x - 10 = 70, x = 16. Present ages: father = 64, son = 16. After 10 years: father = 74, son = 26. Ratio = 74:26 = 37:13. Option C is correct.

Multiple choice

The average age of father and his son is 54 years. After 10 years the ratio of their ages will be in the ratio of 3 : 1 so find the present age of father?

  1. 82 year

  2. 84 year

  3. 86 year

  4. 89 year

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let father's present age be F, son's be S. Average age = 54, so F + S = 108. After 10 years: (F+10) : (S+10) = 3 : 1. So F+10 = 3(S+10), F = 3S + 20. Substituting: 3S + 20 + S = 108, 4S = 88, S = 22. Therefore F = 86. Father's present age is 86 years. Option C is correct.

Multiple choice

5 years ago, Ambika's age is 7 times the daughter's age. The daughter's present age is one-fourth of the Ambika's age. What is Ambika's present age?

  1. 35 years

  2. 40 years

  3. 26 years

  4. 32 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let daughter's present age = d, Ambika's present age = a. 5 years ago: a - 5 = 7(d - 5). Also: d = a/4. Substituting: a - 5 = 7(a/4 - 5). Solving: a - 5 = 7a/4 - 35, so a/4 = 30, a = 120. Wait - checking options: if d = a/4, and a - 5 = 7(d - 5), then a - 5 = 7(a/4 - 5) = 7a/4 - 35. Rearranging: 35 - 5 = 7a/4 - a = 3a/4. So 30 = 3a/4, a = 40. Option B is correct.

Multiple choice

The ratio of ages of Keshav and Saurabh is 4 : 5 and that of Keshav and Hari is 5 : 6. If sum of ages of all the three is 69 years, what is the Saurabh's age?

  1. 20 years

  2. 25 years

  3. 30 years

  4. 35 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Keshav:Saurabh = 4:5 and Keshav:Hari = 5:6. To make Keshav's parts equal, take LCM of 4 and 5, which is 20. Multiply first ratio by 5: Keshav:Saurabh = 20:25. Multiply second ratio by 4: Keshav:Hari = 20:24. So Keshav:Saurabh:Hari = 20:25:24. Total parts = 20+25+24 = 69. Saurabh's age = (25/69) × 69 = 25 years. This matches option B.

Multiple choice

The average age of 6 sons is 8 years and sons and their father's and mother's average age is 22 years. If the father is 8 years elder than mother, then mother's present age?

  1. 44 years

  2. 52 years

  3. 60 years

  4. 68 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total age of 6 sons = 6 × 8 = 48 years. Average of all 8 family members = 22, so their total = 8 × 22 = 176 years. Parents' combined age = 176 - 48 = 128 years. Father is 8 years older than mother: F = M + 8. So M + (M + 8) = 128, giving 2M = 120 or M = 60 years.

Multiple choice

The ratio between the present ages of Rama and Beena is 4:5. Seven years ago the ratio of their ages was 3:4. What is the present age of Beena?

  1. 35 years

  2. 28 years

  3. 21 years

  4. Cannot be determined

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Rama's present age be 4x and Beena's be 5x. Seven years ago: Rama was 4x - 7, Beena was 5x - 7. The ratio was 3:4, so (4x - 7)/(5x - 7) = 3/4. Cross-multiplying: 4(4x - 7) = 3(5x - 7), giving 16x - 28 = 15x - 21, so x = 7. Beena's present age = 5 × 7 = 35 years. The marked answer (A: 35 years) is correct.

Multiple choice

Anshu's present age is four times Priya's age and eight-thirteenth of his father's age. The sum of present ages of all the three is 138 years. What is the difference between the present ages of Priya and Anshu's father?

  1. 66 years

  2. 62 years

  3. 64 years

  4. 60 years

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Priya's age = P. Then Anshu's age = 4P. Anshu's age is 8/13 of father's age, so father's age = (13/8) × 4P = 6.5P. Sum: P + 4P + 6.5P = 11.5P = 138, so P = 12. Father's age = 6.5 × 12 = 78 years. Difference = 78 - 12 = 66 years. Option B (62) is incorrect, Option C (64) is incorrect, Option D (60) is incorrect.