Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

The ages of Samina and Suhana are in the ratio of 7 : 3 respectively.After 6 years the ratio of their ages will be 5 : 3.What is the difference in their ages?

  1. 6 years

  2. 8 years

  3. 10 years

  4. 12 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Samina's present age = 7x and Suhana's present age = 3x (ratio 7:3). After 6 years: (7x + 6) / (3x + 6) = 5/3. Cross-multiplying: 3(7x + 6) = 5(3x + 6), giving 21x + 18 = 15x + 30, so 6x = 12 and x = 2. Present ages: Samina = 14, Suhana = 6. Difference = 14 - 6 = 8 years. This difference remains constant throughout their lives. Option A (6 years) is the age ratio denominator, not the difference. Option C (10 years) and D (12 years) are incorrect calculations.

Multiple choice

Aparna's age is twice Savita's age. What is the difference between their ages? (I) After 5 years, the ratio between their ages will be 9 : 5. (II) 10 years ago, the ratio of their ages was 3 : 1.

  1. If statement I alone is sufficient but statement II alone is not sufficient.

  2. If statement II alone is sufficient but statement I alone is not sufficient.

  3. If each statement alone (either I or II) is sufficient.

  4. If statement I and II together are not sufficient.

  5. If both statements together are sufficient, but neither statement alone is sufficient.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Statement I: After 5 years, ratio is 9:5. If Aparna = 2x, Savita = x, then (2x+5)/(x+5) = 9/5. Solving: 10x+25=9x+45, x=20. Ages: 40 and 20, difference = 20. Statement II: 10 years ago, ratio was 3:1. (2x-10)/(x-10) = 3/1. Solving: 2x-10=3x-30, x=20. Same answer. Either statement alone gives x=20, so difference = 20 years. Both are independently sufficient.

Multiple choice

5 years ago ,the average age of P and Q was 15 years. The present average age of P,Q and R is 20 years.What will be R's age after 10 years?

  1. 35 years

  2. 40 years

  3. 30 years

  4. 50 years

  5. 25 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

5 years ago, average age of P and Q was 15, so their sum was 30. Present sum of P and Q = 30 + 10 = 40. Present average of P, Q, R is 20, so their sum = 60. Thus R's present age = 60 - 40 = 20. After 10 years, R will be 30.

Multiple choice

If twice the son's age is added to father's age, the sum is 75 and if twice the father's age is added to son's age the sum is 90. What is father's age?

  1. 35 years

  2. 40 years

  3. 45 years

  4. 50 years

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let son's age = S, father's age = F. First equation: 2S + F = 75. Second equation: S + 2F = 90. Solve the system: multiply first equation by 2: 4S + 2F = 150. Subtract second equation: (4S + 2F) - (S + 2F) = 150 - 90, giving 3S = 60, so S = 20. Then F = 75 - 2(20) = 35. Father is 35 years old.

Multiple choice

The ratio of present ages of A and B is 4 : 3 respectively. 7 years hence the A’s age will be 43 years what is the present age of C who is 11 years younger than B ?

  1. 16 years

  2. 20 years

  3. 12 years

  4. 10 years

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Present A:B = 4:3. In 7 years, A = 43 years, so present A = 43-7 = 36 years. Since A:B = 4:3, present B = (3/4)×36 = 27 years. C is 11 years younger than B, so C = 27-11 = 16 years. Option A is correct.

Multiple choice

Average age of the mother and her two sons is 27 years. Five years ago, the average age of the two sons was 12 years. If the difference between the ages of the two sons is four years, then the present age of the mother is -

  1. 34 years

  2. 47 years

  3. 64 years

  4. 27 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Current average of mother + 2 sons = 27, so their sum = 3 × 27 = 81 years. Five years ago, sons' average = 12, so their sum = 24, meaning their current sum = 24 + 10 = 34 (5 years each). Let sons be x and x+4 (difference 4). So x + (x+4) = 34, giving 2x = 30, x = 16. Sons are 16 and 20. Mother = 81 - 34 = 47 years.

Multiple choice

The ratio of the ages of A : B seven years ago was (3 : 4) respectively. The ratio of their ages 9 years from now will be (7 : 8) respectively. What is B's age at present?

  1. 29 years

  2. 32 years

  3. 33 years

  4. 23 years

  5. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let A's and B's present ages be 3x+7 and 4x+7. After 9 years: (3x+16)/(4x+16) = 7/8. Cross-multiply: 8(3x+16) = 7(4x+16). 24x+128 = 28x+112. 16 = 4x, so x = 4. B's present age = 4(4)+7 = 23 years. Option D (23 years) is correct. Options A, B, C give 29, 32, 33 which don't satisfy the ratio conditions.

Multiple choice

Meeta's age is twice the Geeta's age and half of the Kumkum's age. What is the ratio of ages of Kumkum, Meeta and Geeta?
  1. $4:2:1$
  2. $3:2:1$
  3. $5:3:2$

  4. Cannot be determined

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Geeta's age = x. Then Meeta = 2x (twice Geeta). Meeta is half of Kumkum, so Kumkum = 4x. The ratio Kumkum:Meeta:Geeta = 4x:2x:x = 4:2:1. Option B (3:2:1) is incorrect - it doesn't satisfy the condition that Meeta is half of Kumkum.

Multiple choice

The age of a father is twice that of his son's at the present age. After 8 years the sum of their ages will be 43 years. How old are they now?

  1. 12 years, 24 years

  2. 9 years, 18 years

  3. 10 years, 20 years

  4. 8 years, 16 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's age = x. Father's age = 2x. After 8 years: (x+8) + (2x+8) = 43. So 3x + 16 = 43, 3x = 27, x = 9. Son is 9 years, father is 18 years now. Option B (9 years, 18 years) is correct. Verification: After 8 years, son will be 17, father will be 26, sum = 43.

Multiple choice

The ratio of father's age to his son's age is 7 : 5. The product of their ages is 875. The ratio of their ages after 7 years will be
  1. $3 : 2$
  2. $21 : 16$
  3. $21 : 8$
  4. $27 : 16$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let father's age = 7x, son's age = 5x. Product = 35x² = 875, so x² = 25, x = 5. Current ages: father = 35, son = 25. After 7 years: father = 42, son = 32. Ratio = 42:32 = 21:16. Always find the actual ages first using the product information.