Quantitative Aptitude
Problems on Ages
1,744 Questions
Problems on Ages Questions
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9 year
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8 years
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3 years
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None of these
A
Correct answer
Explanation
Let F be father, C1, C2, C3 be children. F = C1+C2+C3. After 9 years: F+9 = (C1+9) + (C2+9) = C1+C2+18. Substituting F: C1+C2+C3+9 = C1+C2+18 => C3 = 9.
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19 years
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38 years
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33 years
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14 years
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24 years
D
Correct answer
Explanation
Let x be the son's age. Danish's age at birth was 38 - x. The problem states the son's current age (x) equals Danish's age at birth (38 - x). So, x = 38 - x, which means 2x = 38, so x = 19. Five years ago, the son was 19 - 5 = 14 years old.
C
Correct answer
Explanation
Let ages be 3x and 5x. After 6 years, (3x + 6) / (5x + 6) = 2/3. 9x + 18 = 10x + 12, so x = 6. The difference in ages is 5x - 3x = 2x = 2 * 6 = 12.
C
Correct answer
Explanation
R = x, F = 5x. (5x+6) = 4(x+6). 5x+6 = 4x+24. x = 18.
B
Correct answer
Explanation
Ages are 3x, 6x, 8x. Thrice the sum of eldest and youngest: 3(8x + 3x) = 33x. Six times the other brother: 6(6x) = 36x. Equation: 33x = 36x - 18 => 3x = 18 => x = 6. Ages are 18, 36, 48. Average = (18+36+48)/3 = 102/3 = 34.
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15
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42
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45
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48
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None of these
C
Correct answer
Explanation
Let son's age be x, father's be 3x. After 10 years: 3x+10 = 2(x+10) + 5. 3x+10 = 2x+20+5 => x = 15. Father's age = 3x = 45.
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16 years
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20 years
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14 years
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18 years
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24 years
D
Correct answer
Explanation
Let R be Ray's age, P be Pia's age, and M be Mini's age. We have P = R + 6, P/M = 3/4, and R = M - 14. Substituting M = R + 14 into the ratio gives (R + 6)/(R + 14) = 3/4. Solving 4(R + 6) = 3(R + 14) yields 4R + 24 = 3R + 42, so R = 18.
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12 years
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15 years
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14 years
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None of these
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42 years
A
Correct answer
Explanation
Let J be Joseph's age and E be Eva's age. Seven years ago: J - 7 = 7(E - 7). Three years from now: J + 3 = 3(E + 3). Solving the first gives J = 7E - 42. Substituting into the second: 7E - 42 + 3 = 3E + 9, which simplifies to 4E = 48, so E = 12.
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3x - y = -6, 7x - y = 42
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y - 3x = -6, 7x - y = 49
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3x + y = 4, 7x + y = 42
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4x - y = -1,7x - y = 4
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e
A
Correct answer
Explanation
Seven years ago: (y-7) = 7(x-7) => y-7 = 7x-49 => 7x-y = 42. Three years from now: (y+3) = 3(x+3) => y+3 = 3x+9 => 3x-y = -6.
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21 years
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7 years
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49 years
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3 years
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28 years
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26 years
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24 years
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30 years
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32 years
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34 years
A
Correct answer
Explanation
F = 4D. (F+10) = 2.5(D+10) => 4D + 10 = 2.5D + 25 => 1.5D = 15 => D = 10. Daughter's present age = 10. After 16 years, age = 10 + 16 = 26.
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56 years
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36 years
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63 years
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44 years
B
Correct answer
Explanation
Let ages one year ago be 6x and 7x. Current ages are 6x+1 and 7x+1. Four years hence, ages are 6x+5 and 7x+5. Ratio: (6x+5)/(7x+5) = 7/8. 48x + 40 = 49x + 35, so x = 5. Anushka's current age is 7(5) + 1 = 36.
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90 years
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64 years
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65 years
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87 years
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81 years
D
Correct answer
Explanation
Let ages be A, B, C. A-6 = 2(B-4) => A-6 = 2B-8 => A = 2B-2. C = B+9. C = A-9 => B+9 = A-9 => A = B+18. Equating: 2B-2 = B+18 => B = 20. Then A = 38, C = 29. Sum = 38+20+29 = 87.
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32 years
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40 years
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36 years
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Cannot be determined
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None of these
A
Correct answer
Explanation
Let daughter's age be x, Meena's be 8x. (8x + 8) / (x + 8) = 10 / 3. 24x + 24 = 10x + 80. 14x = 56, x = 4. Meena's age = 8 * 4 = 32.
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14 years
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15 years
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16 years
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17 years
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18 years
A
Correct answer
Explanation
Let Jack's age be 4x and sister's be 7x. 2 years ago: (4x-2)/(7x-2) = 1/2. 8x - 4 = 7x - 2. x = 2. Sister's present age = 7x = 7 * 2 = 14.