Assuming that public class B : A { public B(int i) :base(i) { } } compiles and runs correctly, what can we conclude about the constructors in the class A?

  1. One constructor takes an argument of type i

  2. There is only a default constructor

  3. One constructor takes an arguments of the type int

  4. a and b


Correct Option: C

AI Explanation

To answer this question, let's analyze the given code:

public class B : A {
    public B(int i) : base(i) {
    }
}

This code snippet shows the class B inheriting from class A. The constructor in class B takes an argument of type int and calls the base constructor of class A with the same argument.

Based on this information, we can conclude that:

A. One constructor takes an argument of type i - This option is incorrect because the argument in the constructor of class B is named i, not i itself.

B. There is only a default constructor - This option is incorrect because the presence of the B(int i) constructor in class B indicates that there is a non-default constructor in class A.

C. One constructor takes an argument of the type int - This option is correct because the B(int i) constructor in class B calls the base constructor A(int i), indicating that there is a constructor in class A that takes an argument of type int.

D. a and b - This option is incorrect because option A is incorrect. Only option C is correct.

Therefore, the correct answer is option C.

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