To answer this question, we need to determine the total number of possible handshakes that can occur among the seven people in the group.
When each person shakes hands with each of the other six people, we can consider this as a combination of pairs. Using the combination formula, we can calculate the total number of possible handshakes.
The formula for calculating the number of combinations is:
[C(n, r) = \frac{n!}{r!(n-r)!}]
where (n) is the total number of people and (r) is the number of people in each combination.
In this case, (n = 7) and (r = 2) (since each handshake involves 2 people).
Plugging in the values, we get:
[C(7, 2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2!5!} = \frac{7 \times 6 \times 5!}{2 \times 1 \times 5!} = \frac{7 \times 6}{2 \times 1} = 21]
Therefore, there are a total of 21 handshakes that can occur among the seven people in the group.
Since the given statement states that there are 42 handshakes, which is twice the actual number, the statement is incorrect.
So, the correct answer is B) False.