The matrix form of the linear system $\frac{dx}{dt}=3x-5y\hspace{0.2cm} and\frac {dy}{dt}=4x+8y$ is
-
$\frac{d}{dt}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg) =
\begin{bmatrix}
\ 3 & -5 \\
\ 4 & 8 \\
\end{bmatrix}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg)$
-
$\frac{d}{dt}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg) =
\begin{bmatrix}
\ 3 & 8 \\
\ 4 & -5 \\
\end{bmatrix}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg)$
-
$\frac{d}{dt}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg) =
\begin{bmatrix}
\ 4 & -5 \\
\ 3 & 8 \\
\end{bmatrix}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg)$
-
$\frac{d}{dt}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg) =
\begin{bmatrix}
\ 4 & 8 \\
\ 3 & -5 \\
\end{bmatrix}\bigg(\begin{matrix}
\ x \\
\ y \\
\end{matrix}\bigg)$