A system is described by the following differential equation, where u(t) is the input to the system and y(t) is the output of the system. $\begin{matrix} \ . \ \ y \ \end{matrix}$ (t) + 5y(t) = u(t) when y(0) = 1 and u(t) is a unit step function, y(t) is
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$y(t) = \frac{1}{5}u(t) + \frac{4}{5}e^{-5t}
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\hspace{0.7cm} = 0.2 + 0.8 e^{-5t}$