Multiple choice

Refer to the exhibit. What path will packets from the 192.168.1.0/24 network travel to reach the 10.0.0.0/8 network if RIP is the active routing protocol?

  1. The path will be router A -> router B -> router C -> router E.

  2. The path will be router A -> router D -> router E

  3. Router A will load balance between the router A -> router D -> router E and router A -> router B -> router C -> router E path

  4. Packets will alternate paths depending on the order they arrive at router A.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

RIP uses hop count as its metric and has a maximum of 15 hops (16 is unreachable). Looking at the paths: Path A-B-C-E has 3 hops (A->B, B->C, C->E). Path A-D-E has only 2 hops (A->D, D->E). RIP will choose the path with the lowest hop count, so it will use A->D->E. Option A is wrong because it has more hops. Option C is wrong because RIP doesn't load balance by default across unequal-cost paths. Option D is wrong because RIP doesn't alternate paths based on packet order.

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