Multiple choice

If battery has emf of 12 V with internal resistance as 5.0 x 10-2 W and the current of 90 A, then what is the terminal voltage of the battery?

  1. 7.5 V

  2. 11.95 V

  3. 4.5 V

  4. 16.5 V

  5. 12.05 V
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A Correct answer
Explanation

V = E - Ir Now, E = 12 V, I = 90 Ar = 5 x 10 -2 ΩV = 12 - 90 x 5 x 10 -2 = 7.5 V V = 12 - 4.5 = 7.5 V

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