Multiple choice

Consider the following solutions:

  1. 0.10 m BaCl2 (aq)
  2. 0.12 m K2SO4(aq)
  3. 0.12 m KBr(aq)

Arrange the above solutions in increasing order of their boiling points.

  1. 1 < 2 < 3

  2. 1 < 3 < 2

  3. 2 < 1 < 3

  4. 3 < 1 < 2

  5. 3 < 2 < 1
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Correct answer. Similar molalities, so similar deviations from expected. Expected van't Hoff factor of solutions at given concentration: i expected for BaCl2 = 0.10(3) = 0.30 i expected for K2SO4 = 0.12(3) = 0.36 i expected for KBr = 0.12(2) = 0.24 Higher the van’t Hoff factor, higher will be the boiling point. Hence, correct order of boiling points is KBr < BaCl2 < K2SO4.

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