Multiple choice

A gram molecule of a gas is allowed to expand adiabatically at 327oC till the volume is four times the initial volume. Calculate the amount of heat absorbed. J = 4.2 x 107 ergs/cal, R = 8.31 x 107 ergs/gm mole oC and γ = 1.5

  1. 1187.14 cal

  2. 20941.2 x 1014 cal

  3. 593.57 cal

  4. 2374.28 cal

  5. 3561.42 cal
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A Correct answer
Explanation

 T2 = T1 (V1/ V2)γ -1 = 300K = 270C Hence work done, W = {R/(γ - 1)}( T1 – T2)      = {8.31 x 107/(1.5 - 1)} x 300      = 4986  x 107 Heat absorbed, H = W/J     = 4986 x 107/4.2 x 107    = 1187.14 cal

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