Multiple choice

Calculate the kinetic energy of a gram molecule of argon at 127oC.

  1. 4986 J

  2. 9972 J

  3. 1662 J

  4. 6648 J

  5. 2216 J
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A Correct answer
Explanation

Temperature, T = 1270C                               = 273 + 127                               = 400 K R = 8.31 J/mol K Now K.E. per gram molecule of argon = (3/2) x 8.31 x 400 J             = 4986 J

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