Multiple choice

For an npn transistor connected as shown in figure, VBE = 0.7 Volts. Given that reverse saturation current of the junction at room temperature 300°K is 10-13 A, the emitter current is

  1. 30 mA

  2. 39 mA

  3. 49 mA

  4. 20 mA

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$I_E = I_s \bigg(\frac{V_m}{e m V_r} - 1\bigg) = 10^{-13} \bigg(\frac{0.7}{e^{1 \times 26 \times 10^{-1}}}\bigg) = 49 mA$