Multiple choice

If for a silicon npn transistor, the base-to-emitter voltage (VBE) is 0.7 V and the collector-to-base voltage (VCB) is 0.2 V, then the transistor is operating in the

  1. normal active mode

  2. saturation mode

  3. inverse active mode

  4. cut-off mode
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Here, emitter-base junction is forward biased and base-collector junction is reversed biased. Thus, transistor is operating in normal active region.

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