Multiple choice

In the digital -to- Analog converter circuit shown in the figure below, VR = 10 V and R = 10 k$\Omega$.

The Voltage V0 is

    • 0.781 V
    • 1.562 V
    • 3.125 V
    • 6.250 V
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The net current in inverting terminal of OP - amp is $$L = \dfrac{1}{4}+ \dfrac{1}{16} = \dfrac{5I}{16}$$

So that $V_0 = -R \times \dfrac{5I}{16} = -3.125$

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