Multiple choice

The minimum number of comparators required to build an 8 it flash ADC is

  1. 8

  2. 63

  3. 255

  4. 256
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In the flash analog to digital converter, the no. of comparators is equal to $2^{n-1}$, where n is no. of bits

So, $2^{n-1} = 2^8 - 1 = 255$

Keep practicing — related questions