Multiple choice

In the sum of products function f(X, Y, Z) = $\sum (2,3,4,5)$, the prime implicants are

  1. $\bar XY, X\bar Y$
  2. $\bar XY, X\bar Y \bar Z, X\bar YZ$
  3. $\bar XY\bar Z, \bar XYZ, X\bar Y$
  4. $\bar XY\bar Z, \bar XYZ, X\overline {YZ}, X\bar YZ$
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A Correct answer
Explanation

F= xy'z' + xy'z + x'yz + xyz' = xy'(z' + z) + xy'(z + z') = xy' + x'y

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