In the Op-Amp circuit shown, assume that the diode current follows the equation I = Is exp (V/VT). For Vi = 2V, V0 = V01, and for Vi = 4 V, V0 = V02. The relationship between V01 and V02 is

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V02 = $\sqrt2$V01
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V02 = e2 V01
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V02 = V01 In 2
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V01 - V02 = VT In 2
D
Correct answer
Explanation
Here the inverting terminal is at virtual ground and the current in resistor and diode current is equal i.e.
$$
\begin{aligned}
I_R = & \quad I_D \\
or \qquad \dfrac{V_i}{R} = & \quad I_s e^{\frac{V_0}{V_r}} \\
or \qquad V_D = &\quad V_T\ ln \dfrac{V_i}{I_sR} \\
\text{For the first condition}\\
V_D = 0 - V_{o1} = V_T \ ln \ \dfrac{2}{I_sR}\\
\text{For the first condition}\\
V_D = 0 - V_{o1} = V_T \ ln \ \dfrac{4}{I_sR}\\
\text{Subtracting the above equation}\\
V_{o1} - V_{o2} = &\quad V_T\ ln\dfrac{4}{I_sR} - V_T\ ln \dfrac{2}{I_sR} \\
or \quad V_{o1} - V_{o2} = &\quad V_T\ ln\dfrac{4}{2} = V_T\ ln 2
\end{aligned}
$$