Multiple choice

For an npn transistor connected as shown in figure, VBE = 0.7 Volts. Given that reverse saturation current of the junction at room temperature 300°K is 10-13 A, the emitter current is

  1. 30 mA

  2. 39 mA

  3. 49 mA

  4. 20 mA

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$$I_E = I_s\left(\dfrac{V_{BE}}{enV_r} - 1\right) = 10^{-13}\left(\dfrac{0.7}{e^{1 \times 26 \times 10^{-3}}}-1\right) = 49\ m A $$