Given: 

import java.util.regex.*;   
public class Archie {   
  public static void main(String[] args) {   
    Pattern p = Pattern.compile(args[0]);   
    Matcher m = p.matcher(args[1]);   
    int count = 

    while(m.find())  
       count++;  
     System.out.print(count);  
   }  
 }

And given the command line invocation:
java Archie "\d+" ab2c4d67 What is the result?

technology programming languages

  1. 0

  2. 3

  3. 4

  4. 8

  5. 9

Show answer
Correct Option: B

AI Explanation

To determine the result of the given command line invocation, let's go through the code step by step:

  1. The Pattern.compile(args[0]) line compiles the regular expression passed as the first command line argument ("\d+" in this case) into a pattern.

  2. The Pattern.matcher(args[1]) line creates a matcher object that matches the given input string ("ab2c4d67" in this case) against the pattern.

  3. The variable count is initialized to 0.

  4. The while(m.find()) loop executes as long as there is a match for the pattern in the input string. Each time a match is found, the loop body is executed.

  5. Inside the loop, the count++ statement increments the value of count by 1 for each match found.

  6. After the loop finishes, the value of count is printed using System.out.print(count).

Now, let's analyze the given input string "ab2c4d67" and the regular expression "\d+":

  • The regular expression \d+ matches one or more digits.

  • In the input string "ab2c4d67", there are 3 occurrences of one or more digits: 2, 4, and 67.

Therefore, the correct answer is B. The result printed by the program will be 3.

Find more quizzes: