To determine which options will be included in the output String s
, let's analyze the given code step by step:
String s = "-";
- Initialize the String s
with a hyphen.
Integer x = 343;
- Declare and initialize an Integer variable x
with the value 343.
long L343 = 343L;
- Declare and initialize a long variable L343
with the value 343L.
if(x.equals(L343)) s += ".e1 ";
- This condition checks if the value of x
is equal to the value of L343
. Since x
is an Integer object and L343
is a long, the condition evaluates to false. Therefore, ".e1" is not included in s
.
if(x.equals(343)) s += ".e2 ";
- This condition checks if the value of x
is equal to the value 343. Since x
is an Integer object and 343 is an int, the condition evaluates to true. Therefore, ".e2" is included in s
.
Short s1 = (short)((new Short((short)343)) / (new Short((short)49)));
- Declare and initialize a Short variable s1
by dividing two Short objects, both initialized with the value 343 and 49 respectively. The division result is 7.
if(s1 == 7) s += "=s ";
- This condition checks if the value of s1
is equal to 7. Since s1
is equal to 7, the condition evaluates to true. Therefore, "=s" is included in s
.
if(s1 < new Integer(7+1)) s += "fly ";
- This condition checks if the value of s1
is less than (7+1), which is 8. Since s1
is less than 8, the condition evaluates to true. Therefore, "fly" is included in s
.
System.out.println(s);
- Print the value of s
, which consists of ".e2 =s fly".
Based on the analysis above, the options that will be included in the output String s
are:
B. .e2
C. =s
D. fly
Therefore, the correct answer is B, C, D.