Multiple choice

Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them. I) 2x2 + 12x + 18 = 0 II) 3y2 + 13y + 12 = 0

  1. x > y

  2. x ≥ y

  3. x < y

  4. x ≤ y

  5. x = y or the relation cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

I) 2x^2 + 12x + 18 = 0 -> 2(x^2 + 6x + 9) = 0 -> 2(x+3)^2 = 0 -> x = -3. II) 3y^2 + 13y + 12 = 0 -> (3y+4)(y+3) = 0 -> y = -4/3 or y = -3. Since x = -3 and y is -1.33 or -3, x <= y.

AI explanation

The first equation 2x squared plus 12x plus 18 equals zero is a perfect square that simplifies to (x plus 3) squared equals zero, giving the single solution x equals negative 3. Factoring the second equation gives (3y plus 4) and (y plus 3), meaning y equals negative 1.33 or negative 3. Because negative 3 is less than negative 1.33 and equal to negative 3, x is less than or equal to y.

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