Multiple choice

One alloy of INVAR is composed of nickle, tin and iron in the ratio 12 : 7 : 6, respectively and another alloy of INVAR contains these metals in the ratio 2 : 14 : 9. If equal weights of these alloys are taken and fused together, then what is the ratio of these ingredient metals in the resulting alloy of INVAR?

  1. 2 : 3 : 5

  2. 14 : 21 : 15

  3. 14 : 7 : 15

  4. 7 : 21 : 20

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Alloy 1: 12:7:6 (Total 25). Alloy 2: 2:14:9 (Total 25). Since weights are equal, add the components directly: (12+2) : (7+14) : (6+9) = 14 : 21 : 15.

AI explanation

Since equal weights of the alloys are fused, find the sum of the respective parts for each metal from both alloys. For nickel, the sum is 12 plus 2, which is 14; for tin, the sum is 7 plus 14, which is 21; and for iron, the sum is 6 plus 9, which is 15. The resulting ratio of these ingredients is 14 to 21 to 15.