What is the 15th term of the following series? 2, 4, 6, 8, 10 ...
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What is the 15th term of the following series? 2, 4, 6, 8, 10 ...
24
26
28
30
32
The series is an arithmetic progression with a=2 and d=2. The n-th term is a + (n-1)d. For n=15, term = 2 + (14*2) = 2 + 28 = 30.
Using the arithmetic progression formula for the nth term, where the first term a is 2 and the common difference d is 2, calculate the value of the 15th term. Apply the formula Tn = a + (n - 1)d by substituting the values to get T15 = 2 + (15 - 1)2. Solving this gives 2 + 28, which equals 30.