What is the output of the following script?

$a = 10;
$b = 20;
$c = 4;
$d = 8;
$e = 1.0;
$f = $c + $d * 2;
$g = $f % 20;
$h = $b - $a + $c + 2;
$i = $h << $c;
$j = $i * $e;
print $j;

To find the output of the given script, let's go through each line of code:

$a = 10;
$b = 20;
$c = 4;
$d = 8;
$e = 1.0;

Here, we are assigning values to the variables $a, $b, $c, $d, and $e.

$f = $c + $d * 2;

In this line, $c is added to the result of multiplying $d by 2. $f is assigned the value of 4 + (8 * 2) = 4 + 16 = 20.

$g = $f % 20;

In this line, $g is assigned the remainder when $f is divided by 20. Since $f is equal to 20, the remainder is 0. Therefore, $g is assigned the value of 0.

$h = $b - $a + $c + 2;

In this line, $b is subtracted by $a, and $c is added to the result. Then, 2 is added to the result. $h is assigned the value of 20 - 10 + 4 + 2 = 16.

$i = $h << $c;

In this line, $h is shifted left by $c bits. Since $c is equal to 4, $h is shifted left by 4 positions. Shifting a binary number left by n positions is equivalent to multiplying it by 2^n. So, $i is assigned the value of $h multiplied by 2^4. $i is assigned the value of 16 * 16 = 256.

$j = $i * $e;

In this line, $i is multiplied by $e. Since $i is equal to 256 and $e is equal to 1.0, $j is assigned the value of 256 * 1.0 = 256.

print $j;

Finally, the value of $j, which is 256, is printed as the output.

Therefore, the correct answer is C) 256.

• Thanks
• Wrong explanation