The nth term of the following given sequence is 301. Find the value of n. 4, 7, 11, 16, ...
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The nth term of the following given sequence is 301. Find the value of n. 4, 7, 11, 16, ...
20
21
22
23
The sequence is 4, 7, 11, 16. The differences are 3, 4, 5. This is a quadratic sequence where the nth term is given by n^2/2 + 3n/2 + 2. Setting this equal to 301, n^2 + 3n - 598 = 0. Solving for n using the quadratic formula gives n=23.
This is an arithmetic progression with a first term of 4 and a second term of 7, giving a common difference of 3. The formula for the nth term is a + (n - 1)d, so we set 301 = 4 + (n - 1)3. Solving this equation, 297 = (n - 1)3, which simplifies to n - 1 = 99. Therefore, the value of n is 23.