A can do a piece of work in 180 days and B can do the same work in 240 days. They started the work together but after few days A left the job. B completed the rest of the work in 40 days .Find the number of days in which A worked

The one-day work of A and B is 1/180 and 1/240 respectively. Since B worked alone for the last 40 days, the work completed by B in this period is 40/240, which equals 1/6 of the total job. This leaves 5/6 of the job to be completed by both A and B working together. Their combined one-day work is (4+3)/720 = 7/720, so the time taken by them working together is (5/6) / (7/720). This gives 600/7 days.

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