Raman covers the distance from his school to cricket ground with his usual speed. When he reduces his speed by 5 km/hr, his travel time increases by 5 hours. If he increases his speed by 3 km/hr from his usual speed, he takes 2 hours less than the usual time. What is the distance covered by him?

Using the formula distance equals speed multiplied by time, let the usual speed be s and the usual time be t, so distance D equals s times t. The equations from the problem are s times t equals (s minus 5) times (t plus 5) and s times t equals (s plus 3) times (t minus 2). Expanding these gives 5s equals 5t minus 25 and 3t equals 2s plus 6; solving this system yields s equals 21 kmph and t equals 16 hours. The distance covered is 21 multiplied by 16, which equals 336 km.

• Thanks
• Wrong explanation