31 = 3, 32 = 9, 33 = = 27, 34 = 81, 35 = 243, 36 = 729…
We can find out that the units digit of 3(4n + 3) should be the same as the units digit of 33, which should be 7. Hence, the units digit of 3(4n + 3) - 7 should be 0, which means 3(4n + 3) - 7 can be divided by 5. So the remainder of 3(4n + 3) would be the same as the remainder of 7 divided by 5, which is 2.