Multiple choice

Solve the following equations: $x^{2}y^{2}z^{2}u = 12, x^{2}y^{2}zu^{2} = 8, z^{2}yx^{2}u^{2} = 1, 3xy^{2}z^{2}u^{2} = 4$.

  1. $\left (2,5,\dfrac {1}{2}, \dfrac {1}{5}\right)$
  2. $(2,3,4,7)$
  3. $\left (3, 4,\dfrac {1}{2},\dfrac {1}{3}\right)$
  4. $(0,1,3,5)$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

By substituting the values from option C (x=3, y=4, z=1/2, u=1/3) into the equations: (3^2)(4^2)(1/2^2)(1/3) = 9*16*(1/4)(1/3) = 12. Checking others: (3^2)(4^2)(1/2)(1/3^2) = 9*16(1/2)(1/9) = 8. (1/2^2)(4)(3^2)(1/3^2) = (1/4)*4*9(1/9) = 1. 3(3)(4^2)(1/2^2)(1/3^2) = 3*3*16*(1/4)*(1/9) = 4. All equations hold.

Keep practicing — related questions