Multiple choice

If the frustum of a cone has a height of $6cm$ and radius of $5cm$ and $9cm$ respectively; then its cubical volume will be .............. ${cm}^{3}$.

  1. $320 \pi$
  2. $151 \pi$
  3. $302 \pi$
  4. $98 \pi$
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C Correct answer
Explanation

The volume of a frustum is (1/3) * pi * h * (R^2 + r^2 + R*r). With h=6, R=9, r=5: Volume = (1/3) * pi * 6 * (81 + 25 + 45) = 2 * pi * 151 = 302 * pi.

AI explanation

Using the frustum of a cone volume formula, V equals one third pi h times r one squared plus r two squared plus r one r two. Substituting the values gives one third pi times 6 times 25 plus 81 plus 45, yielding 302 pi cubic cm.

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