Multiple choice

Find the volume of the frustum cone whose base and top radius is $12$ m and $4$m respectively. The height of the cone is $21$ m. (Use $\pi = \dfrac{22}{7}$).

  1. $4,476$ $m^3$
  2. $4,576$ $m^3$
  3. $4,376$$m^3$
  4. $4,276$$m^3$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Volume of frustum = (1/3) * pi * h * (R^2 + r^2 + R*r). V = (1/3) * (22/7) * 21 * (12^2 + 4^2 + 12*4) = 22 * (144 + 16 + 48) = 22 * 208 = 4576.

AI explanation

Apply the frustum of a cone volume formula V = (1/3) pi h (R^2 + r^2 + Rr) using the given values h = 21 m, R = 12 m, and r = 4 m. Substitute these into the formula to get V = (1/3) * (22/7) * 21 * (12^2 + 4^2 + 12 * 4). The terms inside the parentheses sum to 208, and multiplying everything out gives a total volume of 4576 cubic meters.

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