Find three numbers in G.P whose sum is 19 and product is 216

For three numbers in G.P, let them be a/r, a, ar. Sum = a/r + a + ar = 19. Product = (a/r) x a x ar = a³ = 216, so a = 6. Substituting: 6/r + 6 + 6r = 19. Divide by 6: 1/r + 1 + r = 19/6. Multiply by r: 1 + r + r² = 19r/6. This gives r = 1.5 or 2/3. So numbers are 4, 6, 9 (with r = 1.5) or 9, 6, 4 (with r = 2/3). Option A matches one valid ordering.