The ratio of active masses of $22$g $C{O}{2}$, $3g$ ${H}{2}$ and $7g$ ${N}_{2}$ in a gaseous mixture:-

Active mass in a gaseous mixture is proportional to the molar concentration, calculated by dividing the given mass of each gas by its respective molar mass. For carbon dioxide, 22 g divided by 44 g/mol gives 0.5 moles; for hydrogen, 3 g divided by 2 g/mol gives 1.5 moles; and for nitrogen, 7 g divided by 28 g/mol gives 0.25 moles. The ratio of these active masses is 0.5 to 1.5 to 0.25. Multiplying the entire ratio by 2 to clear the decimals results in a final ratio of 1:3:0.5.

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