Multiple choice

A contractor deploys 36 men on a work and in 16 days they complete $\dfrac{2}{3}$rd of the work. To finish the remaining work he deploys 12 men extra. Now the remaining work will be completed in

  1. 7

  2. 6

  3. 9

  4. 3
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Work done = 36 men * 16 days = 576 man-days for 2/3 of work. Total work = 576 * (3/2) = 864 man-days. Remaining work = 1/3 of total = 288 man-days. New men = 36 + 12 = 48. Days = 288 / 48 = 6 days.

AI explanation

Using the unitary method, if 36 men take 16 days to complete two-thirds of the work, the full work would require these 36 men to work for 24 days. This makes the total work 864 man-days, of which 576 man-days are complete, leaving 288 man-days. With 48 men now working, dividing 288 man-days by 48 men results in 6 days to complete the job.

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