Multiple choice

$16$ men can complete a piece of work in $8$ days. In how many days can $12$ men complete the same piece of work?

  1. $11\dfrac{1}{5}$ days
  2. $10\dfrac{2}{3}$ days
  3. $10\dfrac{1}{7}$ days
  4. $11\dfrac{5}{2}$ days
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using the formula M1*D1 = M2*D2, we have 16 * 8 = 12 * D2. Solving for D2 gives 128 / 12 = 32 / 3 = 10 2/3 days.

AI explanation

Using the formula for constant work, $M_1 \times D_1 = M_2 \times D_2$, we substitute the given values as $16 \times 8 = 12 \times \text{days}$. This simplifies to $128 = 12 \times \text{days}$, which yields days $= 10 \frac{2}{3}$.

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