Multiple choice

A group of labourers promises to do piece of work in $10$ days, but five of them become absent . If the remaining labourers complete the work in $12$ days, find their original number in the group.

  1. $18$
  2. $30$
  3. $24$
  4. $36$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let original number be x. Work = 10x. With 5 absent, work = 12(x-5). 10x = 12x - 60, so 2x = 60, x = 30.

AI explanation

Let the original number of laborers be N, making the total work equal to 10N. When 5 laborers are absent, the remaining N-5 laborers complete the 10N work in 12 days, giving the equation 12(N-5) = 10N. Solving for N, 12N - 60 = 10N, yields 2N = 60, so N = 30. The original number of laborers in the group was 30.

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