Which term of the sequence 4, 9, 14, 19, ..., is 124 ?
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Which term of the sequence 4, 9, 14, 19, ..., is 124 ?
25
30
15
35
This is an arithmetic progression with first term a = 4 and common difference d = 5. The n-th term is a + (n-1)d = 124. 4 + (n-1)5 = 124 => (n-1)5 = 120 => n-1 = 24 => n = 25.
The given sequence is an arithmetic progression with the first term a = 4 and the common difference d = 5. Using the formula for the nth term, Tn = a + (n - 1)d, we set Tn = 124 to get 124 = 4 + (n - 1)5. Solving this equation gives 120 = 5(n - 1), which simplifies to n - 1 = 24 and n = 25.