Solve the equations using elimination method: $a -2b = 2$ and $3a -2b = 6$
Reveal answer
Fill a bubble to check yourself
Solve the equations using elimination method: $a -2b = 2$ and $3a -2b = 6$
(2, -1)
(2, 1)
(2, 0)
(-2, 1)
Subtracting the first equation (a - 2b = 2) from the second (3a - 2b = 6) gives 2a = 4, so a = 2. Substituting a = 2 into the first equation: 2 - 2b = 2, so -2b = 0, b = 0. The solution is (2, 0).
Subtract the first equation, a - 2b = 2, from the second equation, 3a - 2b = 6, to eliminate b. This gives 2a = 4, so a = 2. Substituting a = 2 into the first equation yields 2 - 2b = 2, which simplifies to b = 0. The solution is (2, 0).