Multiple choice

How many numbers can be formed using the digits 2, 3, 4, 5, 6 & 7 if no repetition is allowed?

  1. 1956

  2. 3240

  3. 9122

  4. (6! - 2!)/3!

  5. (6)5
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A Correct answer
Explanation

Without repeating we can form 6 one digit numbers. 6 X 5 = 30, two digit numbers. 6 X 5 X 4 = 120, three digit numbers. 6 X 5 X 4 X 3 = 360, four digit numbers. 6 X 5 X 4 X 3 X 2 = 720, five digit numbers and 6 X 5 X 4 X 3 X 2 X 1 = 720 six digit numbers.

Since, this number formation in each case is mutually exclusive we will have to add them all up to arrive at the solution.

So according to problem we can have 6 + 30 + 120 + 360 + 720 + 720 = 1956 numbers.

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