Solve the following pair of equations: $41x + 53y = 135$, $53x + 41y = 147$
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Solve the following pair of equations: $41x + 53y = 135$, $53x + 41y = 147$
Adding the equations: 94x + 94y = 282, so x + y = 3. Subtracting: -12x + 12y = -12, so -x + y = -1. Adding these two results: 2y = 2, y = 1. Then x = 2.
Adding the two equations gives 94x + 94y = 282, which simplifies to x + y = 3. Subtracting the first equation from the second gives 12x - 12y = 12, which simplifies to x - y = 1. Solving this simpler system yields x = 2 and y = 1. The values are x = 2 and y = 1.