Multiple choice

Directions: In the following question, two equations (I) and (II) are given. You have to solve both the equations and give answer. (I) 61x2 - 123x + 2 = 0 (II) 2y2 + 3y + 1 = 0

  1. x > y

  2. x < y

  3. x ≥ y

  4. x ≤ y

  5. x = y or no relation can be established between 'x' and 'y'
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

I: 61x^2 - 123x + 2 = 0. Roots are approx 2 and 0.016. II: 2y^2 + 3y + 1 = 0 => (2y+1)(y+1) = 0. Roots are -0.5 and -1. Since 2 > -0.5 and 0.016 > -1, x > y.

AI explanation

For equation (I) 61x^2 - 123x + 2 = 0, factor the quadratic to get (61x - 2)(x - 1) = 0. The roots for x are 2/61 and 1. For equation (II) 2y^2 + 3y + 1 = 0, factor it to get (2y + 1)(y + 1) = 0. The roots for y are -1/2 and -1. Comparing the roots, both values of x (1 and 2/61) are greater than both negative values of y. Therefore, the relationship x > y is established.

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