The total number of ways to choose 11 players from 15 is 15C11 = 1365. The probability of getting at least 3 bowlers is found by subtracting the probabilities of getting exactly 0, 1, or 2 bowlers from 1. The number of ways to choose 0 bowlers and 11 batsmen is 5C0 times 10C11 = 0, the ways for 1 bowler and 10 batsmen is 5C1 times 10C10 = 5, and the ways for 2 bowlers and 9 batsmen is 5C2 times 10C9 = 10 times 10 = 100. The probability of getting fewer than 3 bowlers is (5 + 100)/1365 = 105/1365 = 1/13. Subtracting this from 1 gives 1 - 1/13 = 12/13.