Calculate the probability of scoring a total of $7$ twice in two tosses of a pair of fair dice.
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Calculate the probability of scoring a total of $7$ twice in two tosses of a pair of fair dice.
The probability of rolling a 7 with two dice is 6/36, which simplifies to 1/6. Since the two tosses are independent events, the probability of scoring a 7 twice is (1/6) * (1/6) = 1/36.
When a pair of dice is tossed, the total number of outcomes is 36, and the number of outcomes that give a sum of 7 is 6: (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1). The probability of scoring a total of 7 in a single toss is therefore 6/36 or 1/6. For two independent tosses, the probability of scoring a 7 both times is found by multiplying the individual probabilities: 1/6 * 1/6 = 1/36.