The mean deviation of the following distribution is x 10 11 12 13 14 f 3 12 18 12 3

The total number of observations is the sum of the frequencies: 3 + 12 + 18 + 12 + 3 = 48. Using the assumed mean method with A = 12, the mean is 12 + (3(-2) + 12(-1) + 18(0) + 12(1) + 3(2)) / 48 = 12 + 0 = 12. The absolute deviations from the mean are |10-12|=2, |11-12|=1, |12-12|=0, |13-12|=1, and |14-12|=2. The mean deviation is (3(2) + 12(1) + 18(0) + 12(1) + 3(2)) / 48 = 36 / 48. The result is 0.75.

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