What will happen if you try to compile and run the following code? public class Q { public static void main(String argv[]){ int anar[]=new int[5]; System.out.println(anar[0]); } }

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  1. Error: anar is referenced before it is initialized

  2. null

  3. 0

  4. 5

Show answer
Correct Option: C

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Error: anar is referenced before it is initialized - This option is incorrect. The array "anar" is initialized with a size of 5 using the line "int anar[]=new int[5];". Therefore, it is not referenced before it is initialized.

Option B) null - This option is incorrect. In Java, arrays of primitive types are initialized with default values. For an array of integers, the default value is 0. Therefore, the first element of the array "anar" will be 0.

Option C) 0 - This option is correct. The code prints the value of the first element of the array "anar" using the line "System.out.println(anar[0]);". Since the array is initialized with a size of 5 but not explicitly initialized with any values, all elements in the array will have the default value of 0. Therefore, the code will print 0.

Option D) 5 - This option is incorrect. The array is initialized with a size of 5, but the elements in the array are not explicitly initialized with the value 5. Therefore, the code will not print 5.

The correct answer is C) 0. This option is correct because the code will print the value of the first element of the array "anar", which is 0.

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